remove-nth-node-from-end-of-list
19. Remove Nth Node From End of List
Given the head
of a linked list, remove the nth
node from the end of the list and return its head.
Example 1:
Input: head = [1,2,3,4,5], n = 2 Output: [1,2,3,5]
Example 2:
Input: head = [1], n = 1 Output: []
Example 3:
Input: head = [1,2], n = 1 Output: [1]
Constraints:
- The number of nodes in the list is
sz
. 1 <= sz <= 30
0 <= Node.val <= 100
1 <= n <= sz
Follow up: Could you do this in one pass?
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* removeNthFromEnd(ListNode* head, int n) {
ListNode* slow = head;
ListNode* fast = head;
for(int i = 0; i < n; i++) {
fast = fast->next;
}
if(!fast) return head->next;
while(fast && fast->next) {
slow = slow->next;
fast = fast->next;
}
slow->next = slow->next->next;
return head;
}
};
- T:
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